A bag consists of a number of 10-cent and 50-cent coins. There are 85% as many 10-cent coins as 50-cent coins. How much money is there in the bag if there are 30 more 50-cent coins than 10-cent coins?
85% =
85100 =
1720
10-cent |
50-cent |
Difference |
17 u |
20 u |
3 u |
Number of 10-cent coins = 17 u
Number of 50-cent coins = 20 u
Difference in the number of coins = 20 u - 17 u = 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of 50-cent coins
= 20 u
= 20 x 10
= 200
Number of 10-cent coins
= 17 u
= 17 x 10
= 170
Amount of money in the bag
= 170 x 0.10 + 200 x 0.50
= 17 + 100
= $117
Answer(s): $117