A fruit vendor ordered some fruits. 25% of the fruits he ordered were pomegranates and the rest were kiwis. Each pomegranate cost $2.40 and each kiwi cost 50% more than each pomegranate. The vendor paid a total of $66.
- Find the total cost of the pomegranates.
- How many kiwis did he order?
(a)
| |
Pomegranates |
Kiwis |
| Numbers |
1 u |
3 u |
| Price |
$2.40 |
$3.60 |
| Total value |
2.4 u |
10.8 u |
25% =
25100 =
14Number of pomegranates = 1 u
Number of kiwis = 4 u - 1 u = 3 u
Price of each pomegranate in percent = 100%
Price of each kiwi in percent = 100% + 50% = 150%
Price of each kiwi
= 2.40 x 150%
= 2.40 x
150100 = $3.60
2.4 u + 10.8 u = 66
13.2 u = 66
1 u = 66 ÷ 13.2 = 5
Cost of the pomegranates
= 1 u x 2.40
= 1 x 5 x 2.40
= $12
(b)
Number of kiwis ordered
= 3 u
= 3 x 5
= 15
Answer(s): (a) $12; (b) 15
