A fruit vendor ordered some fruits. 35% of the fruits he ordered were pears and the rest were pomegranates. Each pear cost $2.50 and each pomegranate cost 40% more than each pear. The vendor paid a total of $630.
- Find the total cost of the pears.
- How many pomegranates did he order?
(a)
| |
Pears |
Pomegranates |
| Numbers |
7 u |
13 u |
| Price |
$2.50 |
$3.50 |
| Total value |
17.5 u |
45.5 u |
35% =
35100 =
720Number of pears = 7 u
Number of pomegranates = 20 u - 7 u = 13 u
Price of each pear in percent = 100%
Price of each pomegranate in percent = 100% + 40% = 140%
Price of each pomegranate
= 2.50 x 140%
= 2.50 x
140100 = $3.50
17.5 u + 45.5 u = 630
63 u = 630
1 u = 630 ÷ 63 = 10
Cost of the pears
= 7 u x 2.50
= 7 x 10 x 2.50
= $175
(b)
Number of pomegranates ordered
= 13 u
= 13 x 10
= 130
Answer(s): (a) $175; (b) 130
