A fruit vendor ordered some fruits. 25% of the fruits he ordered were pears and the rest were kiwis. Each pear cost $2.80 and each kiwi cost 50% more than each pear. The vendor paid a total of $77.
- Find the total cost of the pears.
- How many kiwis did he order?
(a)
|
Pears |
Kiwis |
Numbers |
1 u |
3 u |
Price |
$2.80 |
$4.20 |
Total value |
2.8 u |
12.6 u |
25% =
25100 =
14Number of pears = 1 u
Number of kiwis = 4 u - 1 u = 3 u
Price of each pear in percent = 100%
Price of each kiwi in percent = 100% + 50% = 150%
Price of each kiwi
= 2.80 x 150%
= 2.80 x
150100 = $4.20
2.8 u + 12.6 u = 77
15.4 u = 77
1 u = 77 ÷ 15.4 = 5
Cost of the pears
= 1 u x 2.80
= 1 x 5 x 2.80
= $14
(b)
Number of kiwis ordered
= 3 u
= 3 x 5
= 15
Answer(s): (a) $14; (b) 15