A fruit vendor ordered some fruits. 25% of the fruits he ordered were pears and the rest were pomegranates. Each pear cost $1.40 and each pomegranate cost 50% more than each pear. The vendor paid a total of $154.
- Find the total cost of the pears.
- How many pomegranates did he order?
(a)
| |
Pears |
Pomegranates |
| Numbers |
1 u |
3 u |
| Price |
$1.40 |
$2.10 |
| Total value |
1.4 u |
6.3 u |
25% =
25100 =
14Number of pears = 1 u
Number of pomegranates = 4 u - 1 u = 3 u
Price of each pear in percent = 100%
Price of each pomegranate in percent = 100% + 50% = 150%
Price of each pomegranate
= 1.40 x 150%
= 1.40 x
150100 = $2.10
1.4 u + 6.3 u = 154
7.7 u = 154
1 u = 154 ÷ 7.7 = 20
Cost of the pears
= 1 u x 1.40
= 1 x 20 x 1.40
= $28
(b)
Number of pomegranates ordered
= 3 u
= 3 x 20
= 60
Answer(s): (a) $28; (b) 60
