A fruit vendor ordered some fruits. 40% of the fruits he ordered were persimmons and the rest were pears. Each persimmon cost $2.60 and each pear cost 50% more than each persimmon. The vendor paid a total of $338.
- Find the total cost of the persimmons.
- How many pears did he order?
(a)
| |
Persimmons |
Pears |
| Numbers |
2 u |
3 u |
| Price |
$2.60 |
$3.90 |
| Total value |
5.2 u |
11.7 u |
40% =
40100 =
25Number of persimmons = 2 u
Number of pears = 5 u - 2 u = 3 u
Price of each persimmon in percent = 100%
Price of each pear in percent = 100% + 50% = 150%
Price of each pear
= 2.60 x 150%
= 2.60 x
150100 = $3.90
5.2 u + 11.7 u = 338
16.9 u = 338
1 u = 338 ÷ 16.9 = 20
Cost of the persimmons
= 2 u x 2.60
= 2 x 20 x 2.60
= $104
(b)
Number of pears ordered
= 3 u
= 3 x 20
= 60
Answer(s): (a) $104; (b) 60
