A fruit vendor ordered some fruits. 25% of the fruits he ordered were lemons and the rest were pears. Each lemon cost $2.50 and each pear cost 40% more than each lemon. The vendor paid a total of $351.
- Find the total cost of the lemons.
- How many pears did he order?
(a)
| |
Lemons |
Pears |
| Numbers |
1 u |
3 u |
| Price |
$2.50 |
$3.50 |
| Total value |
2.5 u |
10.5 u |
25% =
25100 =
14Number of lemons = 1 u
Number of pears = 4 u - 1 u = 3 u
Price of each lemon in percent = 100%
Price of each pear in percent = 100% + 40% = 140%
Price of each pear
= 2.50 x 140%
= 2.50 x
140100 = $3.50
2.5 u + 10.5 u = 351
13 u = 351
1 u = 351 ÷ 13 = 27
Cost of the lemons
= 1 u x 2.50
= 1 x 27 x 2.50
= $67.5
(b)
Number of pears ordered
= 3 u
= 3 x 27
= 81
Answer(s): (a) $67.5; (b) 81
