A fruit vendor ordered some fruits. 35% of the fruits he ordered were pomegranates and the rest were lemons. Each pomegranate cost $2.80 and each lemon cost 50% more than each pomegranate. The vendor paid a total of $1113.
- Find the total cost of the pomegranates.
- How many lemons did he order?
(a)
|
Pomegranates |
Lemons |
Numbers |
7 u |
13 u |
Price |
$2.80 |
$4.20 |
Total value |
19.6 u |
54.6 u |
35% =
35100 =
720Number of pomegranates = 7 u
Number of lemons = 20 u - 7 u = 13 u
Price of each pomegranate in percent = 100%
Price of each lemon in percent = 100% + 50% = 150%
Price of each lemon
= 2.80 x 150%
= 2.80 x
150100 = $4.20
19.6 u + 54.6 u = 1113
74.2 u = 1113
1 u = 1113 ÷ 74.2 = 15
Cost of the pomegranates
= 7 u x 2.80
= 7 x 15 x 2.80
= $294
(b)
Number of lemons ordered
= 13 u
= 13 x 15
= 195
Answer(s): (a) $294; (b) 195