A fruit vendor ordered some fruits. 45% of the fruits he ordered were lemons and the rest were pomegranates. Each lemon cost $2.50 and each pomegranate cost 40% more than each lemon. The vendor paid a total of $366.
- Find the total cost of the lemons.
- How many pomegranates did he order?
(a)
| |
Lemons |
Pomegranates |
| Numbers |
9 u |
11 u |
| Price |
$2.50 |
$3.50 |
| Total value |
22.5 u |
38.5 u |
45% =
45100 =
920Number of lemons = 9 u
Number of pomegranates = 20 u - 9 u = 11 u
Price of each lemon in percent = 100%
Price of each pomegranate in percent = 100% + 40% = 140%
Price of each pomegranate
= 2.50 x 140%
= 2.50 x
140100 = $3.50
22.5 u + 38.5 u = 366
61 u = 366
1 u = 366 ÷ 61 = 6
Cost of the lemons
= 9 u x 2.50
= 9 x 6 x 2.50
= $135
(b)
Number of pomegranates ordered
= 11 u
= 11 x 6
= 66
Answer(s): (a) $135; (b) 66
