A fruit vendor ordered some fruits. 40% of the fruits he ordered were pears and the rest were mangoes. Each pear cost $1.80 and each mango cost 50% more than each pear. The vendor paid a total of $234.
- Find the total cost of the pears.
- How many mangoes did he order?
(a)
|
Pears |
Mangoes |
Numbers |
2 u |
3 u |
Price |
$1.80 |
$2.70 |
Total value |
3.6 u |
8.1 u |
40% =
40100 =
25Number of pears = 2 u
Number of mangoes = 5 u - 2 u = 3 u
Price of each pear in percent = 100%
Price of each mango in percent = 100% + 50% = 150%
Price of each mango
= 1.80 x 150%
= 1.80 x
150100 = $2.70
3.6 u + 8.1 u = 234
11.7 u = 234
1 u = 234 ÷ 11.7 = 20
Cost of the pears
= 2 u x 1.80
= 2 x 20 x 1.80
= $72
(b)
Number of mangoes ordered
= 3 u
= 3 x 20
= 60
Answer(s): (a) $72; (b) 60