A fruit vendor ordered some fruits. 45% of the fruits he ordered were pears and the rest were lemons. Each pear cost $1.50 and each lemon cost 20% more than each pear. The vendor paid a total of $333.
- Find the total cost of the pears.
- How many lemons did he order?
(a)
| |
Pears |
Lemons |
| Numbers |
9 u |
11 u |
| Price |
$1.50 |
$1.80 |
| Total value |
13.5 u |
19.8 u |
45% =
45100 =
920Number of pears = 9 u
Number of lemons = 20 u - 9 u = 11 u
Price of each pear in percent = 100%
Price of each lemon in percent = 100% + 20% = 120%
Price of each lemon
= 1.50 x 120%
= 1.50 x
120100 = $1.80
13.5 u + 19.8 u = 333
33.3 u = 333
1 u = 333 ÷ 33.3 = 10
Cost of the pears
= 9 u x 1.50
= 9 x 10 x 1.50
= $135
(b)
Number of lemons ordered
= 11 u
= 11 x 10
= 110
Answer(s): (a) $135; (b) 110
