A fruit vendor ordered some fruits. 45% of the fruits he ordered were persimmons and the rest were pomegranates. Each persimmon cost $1.50 and each pomegranate cost 40% more than each persimmon. The vendor paid a total of $366.
- Find the total cost of the persimmons.
- How many pomegranates did he order?
(a)
|
Persimmons |
Pomegranates |
Numbers |
9 u |
11 u |
Price |
$1.50 |
$2.10 |
Total value |
13.5 u |
23.1 u |
45% =
45100 =
920Number of persimmons = 9 u
Number of pomegranates = 20 u - 9 u = 11 u
Price of each persimmon in percent = 100%
Price of each pomegranate in percent = 100% + 40% = 140%
Price of each pomegranate
= 1.50 x 140%
= 1.50 x
140100 = $2.10
13.5 u + 23.1 u = 366
36.6 u = 366
1 u = 366 ÷ 36.6 = 10
Cost of the persimmons
= 9 u x 1.50
= 9 x 10 x 1.50
= $135
(b)
Number of pomegranates ordered
= 11 u
= 11 x 10
= 110
Answer(s): (a) $135; (b) 110