A fruit vendor ordered some fruits. 25% of the fruits he ordered were pears and the rest were chikoos. Each pear cost $2.50 and each chikoo cost 40% more than each pear. The vendor paid a total of $338.
- Find the total cost of the pears.
- How many chikoos did he order?
(a)
| |
Pears |
Chikoos |
| Numbers |
1 u |
3 u |
| Price |
$2.50 |
$3.50 |
| Total value |
2.5 u |
10.5 u |
25% =
25100 =
14Number of pears = 1 u
Number of chikoos = 4 u - 1 u = 3 u
Price of each pear in percent = 100%
Price of each chikoo in percent = 100% + 40% = 140%
Price of each chikoo
= 2.50 x 140%
= 2.50 x
140100 = $3.50
2.5 u + 10.5 u = 338
13 u = 338
1 u = 338 ÷ 13 = 26
Cost of the pears
= 1 u x 2.50
= 1 x 26 x 2.50
= $65
(b)
Number of chikoos ordered
= 3 u
= 3 x 26
= 78
Answer(s): (a) $65; (b) 78
