A fruit vendor ordered some fruits. 45% of the fruits he ordered were pears and the rest were kiwis. Each pear cost $2.80 and each kiwi cost 50% more than each pear. The vendor paid a total of $1071.
- Find the total cost of the pears.
- How many kiwis did he order?
(a)
|
Pears |
Kiwis |
Numbers |
9 u |
11 u |
Price |
$2.80 |
$4.20 |
Total value |
25.2 u |
46.2 u |
45% =
45100 =
920Number of pears = 9 u
Number of kiwis = 20 u - 9 u = 11 u
Price of each pear in percent = 100%
Price of each kiwi in percent = 100% + 50% = 150%
Price of each kiwi
= 2.80 x 150%
= 2.80 x
150100 = $4.20
25.2 u + 46.2 u = 1071
71.4 u = 1071
1 u = 1071 ÷ 71.4 = 15
Cost of the pears
= 9 u x 2.80
= 9 x 15 x 2.80
= $378
(b)
Number of kiwis ordered
= 11 u
= 11 x 15
= 165
Answer(s): (a) $378; (b) 165