At the bus transit terminal, 62.5% of the passengers were female and the rest were male. After 8 male passengers entered the terminal, the percentage of the number of male passengers became 50%. Find the number of male passengers at the terminal at first.
|
Female |
Male |
Before |
5x1 = 5 u |
3x1 = 3 u |
Change |
No change |
+ 8 |
After |
1x5 = 5 u |
1x5 = 5 u |
62.5% =
6251000 =
5850% =
50100 =
12The number of female passengers at first and in the end remains unchanged. Make the number of female passengers the same. LCM of 5 and 1 is 5.
Number of male passengers who entered the terminal
= 5 u - 3 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of male passengers at the terminal at first
= 3 u
= 3 x 4
= 12
Answer(s): 12