At the bus transit terminal, 37.5% of the passengers were male and the rest were female. After 60 female passengers left the terminal, the percentage of the number of female passengers became 55%. Find the number of female passengers at the terminal at first.
|
Male |
Female |
Before |
3x3 = 9 u |
5x3 = 15 u |
Change |
No change |
- 60 |
After |
9x1 = 9 u |
11x1 = 11 u |
37.5% =
3751000 =
3855% =
55100 =
1120The number of male passengers at first and in the end remains unchanged. Make the number of male passengers the same. LCM of 3 and 9 is 9.
Number of female passengers who left the terminal
= 15 u - 11 u
= 4 u
4 u = 60
1 u = 60 ÷ 4 = 15
Number of female passengers at the terminal at first
= 15 u
= 15 x 15
= 225
Answer(s): 225