At the bus transit terminal, 12.5% of the passengers were female and the rest were male. After 60 male passengers left the terminal, the percentage of the number of male passengers became 50%. Find the number of male passengers at the terminal at first.
| |
Female |
Male |
| Before |
1x1 =
1 u |
7x1 =
7 u |
| Change |
No change |
- 60 |
| After |
1x1 =
1 u |
1x1 =
1 u |
12.5% =
1251000 =
1850% =
50100 =
12The number of female passengers at first and in the end remains unchanged. Make the number of female passengers the same. LCM of 1 and 1 is 1.
Number of male passengers who left the terminal
= 7 u - 1 u
= 6 u
6 u = 60
1 u = 60 ÷ 6 = 10
Number of male passengers at the terminal at first
= 7 u
= 7 x 10
= 70
Answer(s): 70
