At the bus transit terminal, 62.5% of the passengers were male and the rest were female. After 72 female passengers entered the terminal, the percentage of the number of female passengers became 60%. Find the number of female passengers at the terminal at first.
| |
Male |
Female |
| Before |
5x2 =
10 u |
3x2 =
6 u |
| Change |
No change |
+ 72 |
| After |
2x5 =
10 u |
3x5 =
15 u |
62.5% =
6251000 =
5860% =
60100 =
35The number of male passengers at first and in the end remains unchanged. Make the number of male passengers the same. LCM of 5 and 2 is 10.
Number of female passengers who entered the terminal
= 15 u - 6 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Number of female passengers at the terminal at first
= 6 u
= 6 x 8
= 48
Answer(s): 48
