⁵₇ of Howard's savings comprised of 10-cent coins and 50-cent coins. Howard used some 10-cent coins to purchase a basketball set. The number of 50-cent coins left was 25% more than the number of 10-cent coins left. Given that Howard had 40 more 50-cent coins than 10-cent coins left in the end, find the amount of money Howard spent on the basketball set.

	10-cent coins	50-cent coins
Before	5x5 = 25 u	2x5 = 10 u
Change	- 17 u
After	4x2 = 8 u	5x2 = 10 u

Fraction of Howard's savings that comprised of 50-cent coins
= 1 - ⁵₇
= ²₇

Number of 50-cents coins in the end in percentage
= 100% + 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same.  LCM of 2 and 5 is 10.

Number of more 50-cent coins than 10-cent coins
= 10 u - 8 u
= 2 u

2 u = 40

1 u = 40 ÷ 2 = 20

Number of 10-cent coins spent on the basketball set 
= 25 u - 8 u
= 17 u
= 17 x 20
= 340

Amount that Howard spent on the basketball set 
= 340 x 0.1
= $34

Answer(s): $34