57 of Fabian's savings comprised of 20-cent coins and 10-cent coins. Fabian used some 20-cent coins to purchase a game card. The number of 10-cent coins left was 50% more than the number of 20-cent coins left. Given that Fabian had 10 more 10-cent coins than 20-cent coins left in the end, find the amount of money Fabian spent on the game card.
|
20-cent coins |
10-cent coins |
Before |
5x3 = 15 u |
2x3 = 6 u |
Change |
- 11 u |
|
After |
2x2 = 4 u |
3x2 = 6 u |
Fraction of Fabian's savings that comprised of 10-cent coins
= 1 -
57=
27Number of 10-cents coins in the end in percentage
= 100% + 50%
= 150%
150% =
150100 =
32Number of 10-cent coins remains unchanged. Make the number of 10-cent coins the same. LCM of 2 and 3 is 6.
Number of more 10-cent coins than 20-cent coins
= 6 u - 4 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of 20-cent coins spent on the game card
= 15 u - 4 u
= 11 u
= 11 x 5
= 55
Amount that Fabian spent on the game card
= 55 x 0.2
= $11
Answer(s): $11