56 of Archie's savings comprised of 10-cent coins and 20-cent coins. Archie used some 10-cent coins to purchase a marble. The number of 20-cent coins left was 40% more than the number of 10-cent coins left. Given that Archie had 6 more 20-cent coins than 10-cent coins left in the end, find the amount of money Archie spent on the marble.
|
10-cent coins |
20-cent coins |
Before |
5x7 = 35 u |
1x7 = 7 u |
Change |
- 30 u |
|
After |
5x1 = 5 u |
7x1 = 7 u |
Fraction of Archie's savings that comprised of 20-cent coins
= 1 -
56=
16Number of 20-cents coins in the end in percentage
= 100% + 40%
= 140%
140% =
140100 =
75Number of 20-cent coins remains unchanged. Make the number of 20-cent coins the same. LCM of 1 and 7 is 7.
Number of more 20-cent coins than 10-cent coins
= 7 u - 5 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Number of 10-cent coins spent on the marble
= 35 u - 5 u
= 30 u
= 30 x 3
= 90
Amount that Archie spent on the marble
= 90 x 0.1
= $9
Answer(s): $9