59 of Ryan's savings comprised of 5-cent coins and 20-cent coins. Ryan used some 5-cent coins to purchase a basketball set. The number of 20-cent coins left was 40% more than the number of 5-cent coins left. Given that Ryan had 32 more 20-cent coins than 5-cent coins left in the end, find the amount of money Ryan spent on the basketball set.
|
5-cent coins |
20-cent coins |
Before |
5x7 = 35 u |
4x7 = 28 u |
Change |
- 15 u |
|
After |
5x4 = 20 u |
7x4 = 28 u |
Fraction of Ryan's savings that comprised of 20-cent coins
= 1 -
59=
49Number of 20-cents coins in the end in percentage
= 100% + 40%
= 140%
140% =
140100 =
75Number of 20-cent coins remains unchanged. Make the number of 20-cent coins the same. LCM of 4 and 7 is 28.
Number of more 20-cent coins than 5-cent coins
= 28 u - 20 u
= 8 u
8 u = 32
1 u = 32 ÷ 8 = 4
Number of 5-cent coins spent on the basketball set
= 35 u - 20 u
= 15 u
= 15 x 4
= 60
Amount that Ryan spent on the basketball set
= 60 x 0.05
= $3
Answer(s): $3