³₅ of Jenson's savings comprised of 10-cent coins and 50-cent coins. Jenson used some 10-cent coins to purchase a yoyo. The number of 50-cent coins left was 50% more than the number of 10-cent coins left. Given that Jenson had 32 more 50-cent coins than 10-cent coins left in the end, find the amount of money Jenson spent on the yoyo.

	10-cent coins	50-cent coins
Before	3x3 = 9 u	2x3 = 6 u
Change	- 5 u
After	2x2 = 4 u	3x2 = 6 u

Fraction of Jenson's savings that comprised of 50-cent coins
= 1 - ³₅
= ²₅

Number of 50-cents coins in the end in percentage
= 100% + 50%
= 150%

150% = ¹⁵⁰₁₀₀ = ³₂

Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same.  LCM of 2 and 3 is 6.

Number of more 50-cent coins than 10-cent coins
= 6 u - 4 u
= 2 u

2 u = 32

1 u = 32 ÷ 2 = 16

Number of 10-cent coins spent on the yoyo 
= 9 u - 4 u
= 5 u
= 5 x 16
= 80

Amount that Jenson spent on the yoyo 
= 80 x 0.1
= $8

Answer(s): $8