⁷₉ of Fabian's savings comprised of 10-cent coins and 50-cent coins. Fabian used some 10-cent coins to purchase a board game. The number of 50-cent coins left was 50% more than the number of 10-cent coins left. Given that Fabian had 40 more 50-cent coins than 10-cent coins left in the end, find the amount of money Fabian spent on the board game.

	10-cent coins	50-cent coins
Before	7x3 = 21 u	2x3 = 6 u
Change	- 17 u
After	2x2 = 4 u	3x2 = 6 u

Fraction of Fabian's savings that comprised of 50-cent coins
= 1 - ⁷₉
= ²₉

Number of 50-cents coins in the end in percentage
= 100% + 50%
= 150%

150% = ¹⁵⁰₁₀₀ = ³₂

Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same.  LCM of 2 and 3 is 6.

Number of more 50-cent coins than 10-cent coins
= 6 u - 4 u
= 2 u

2 u = 40

1 u = 40 ÷ 2 = 20

Number of 10-cent coins spent on the board game 
= 21 u - 4 u
= 17 u
= 17 x 20
= 340

Amount that Fabian spent on the board game 
= 340 x 0.1
= $34

Answer(s): $34