59 of Jeremy's savings comprised of 20-cent coins and 50-cent coins. Jeremy used some 20-cent coins to purchase a basketball set. The number of 50-cent coins left was 40% more than the number of 20-cent coins left. Given that Jeremy had 32 more 50-cent coins than 20-cent coins left in the end, find the amount of money Jeremy spent on the basketball set.
|
20-cent coins |
50-cent coins |
Before |
5x7 = 35 u |
4x7 = 28 u |
Change |
- 15 u |
|
After |
5x4 = 20 u |
7x4 = 28 u |
Fraction of Jeremy's savings that comprised of 50-cent coins
= 1 -
59=
49Number of 50-cents coins in the end in percentage
= 100% + 40%
= 140%
140% =
140100 =
75Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same. LCM of 4 and 7 is 28.
Number of more 50-cent coins than 20-cent coins
= 28 u - 20 u
= 8 u
8 u = 32
1 u = 32 ÷ 8 = 4
Number of 20-cent coins spent on the basketball set
= 35 u - 20 u
= 15 u
= 15 x 4
= 60
Amount that Jeremy spent on the basketball set
= 60 x 0.2
= $12
Answer(s): $12