⁵₉ of Howard's savings comprised of 20-cent coins and 10-cent coins. Howard used some 20-cent coins to purchase a frisbee. The number of 10-cent coins left was 50% more than the number of 20-cent coins left. Given that Howard had 40 more 10-cent coins than 20-cent coins left in the end, find the amount of money Howard spent on the frisbee.

	20-cent coins	10-cent coins
Before	5x3 = 15 u	4x3 = 12 u
Change	- 7 u
After	2x4 = 8 u	3x4 = 12 u

Fraction of Howard's savings that comprised of 10-cent coins
= 1 - ⁵₉
= ⁴₉

Number of 10-cents coins in the end in percentage
= 100% + 50%
= 150%

150% = ¹⁵⁰₁₀₀ = ³₂

Number of 10-cent coins remains unchanged. Make the number of 10-cent coins the same.  LCM of 4 and 3 is 12.

Number of more 10-cent coins than 20-cent coins
= 12 u - 8 u
= 4 u

4 u = 40

1 u = 40 ÷ 4 = 10

Number of 20-cent coins spent on the frisbee 
= 15 u - 8 u
= 7 u
= 7 x 10
= 70

Amount that Howard spent on the frisbee 
= 70 x 0.2
= $14

Answer(s): $14