³₅ of Xavier's savings comprised of 20-cent coins and 10-cent coins. Xavier used some 20-cent coins to purchase a toy figurine. The number of 10-cent coins left was 25% more than the number of 20-cent coins left. Given that Xavier had 20 more 10-cent coins than 20-cent coins left in the end, find the amount of money Xavier spent on the toy figurine.

	20-cent coins	10-cent coins
Before	3x5 = 15 u	2x5 = 10 u
Change	- 7 u
After	4x2 = 8 u	5x2 = 10 u

Fraction of Xavier's savings that comprised of 10-cent coins
= 1 - ³₅
= ²₅

Number of 10-cents coins in the end in percentage
= 100% + 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Number of 10-cent coins remains unchanged. Make the number of 10-cent coins the same.  LCM of 2 and 5 is 10.

Number of more 10-cent coins than 20-cent coins
= 10 u - 8 u
= 2 u

2 u = 20

1 u = 20 ÷ 2 = 10

Number of 20-cent coins spent on the toy figurine 
= 15 u - 8 u
= 7 u
= 7 x 10
= 70

Amount that Xavier spent on the toy figurine 
= 70 x 0.2
= $14

Answer(s): $14