35 of Tim's savings comprised of 5-cent coins and 20-cent coins. Tim used some 5-cent coins to purchase a game card. The number of 20-cent coins left was 50% more than the number of 5-cent coins left. Given that Tim had 16 more 20-cent coins than 5-cent coins left in the end, find the amount of money Tim spent on the game card.
|
5-cent coins |
20-cent coins |
Before |
3x3 = 9 u |
2x3 = 6 u |
Change |
- 5 u |
|
After |
2x2 = 4 u |
3x2 = 6 u |
Fraction of Tim's savings that comprised of 20-cent coins
= 1 -
35=
25Number of 20-cents coins in the end in percentage
= 100% + 50%
= 150%
150% =
150100 =
32Number of 20-cent coins remains unchanged. Make the number of 20-cent coins the same. LCM of 2 and 3 is 6.
Number of more 20-cent coins than 5-cent coins
= 6 u - 4 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of 5-cent coins spent on the game card
= 9 u - 4 u
= 5 u
= 5 x 8
= 40
Amount that Tim spent on the game card
= 40 x 0.05
= $2
Answer(s): $2