89 of Ryan's savings comprised of 20-cent coins and 50-cent coins. Ryan used some 20-cent coins to purchase a doll set. The number of 50-cent coins left was 40% more than the number of 20-cent coins left. Given that Ryan had 20 more 50-cent coins than 20-cent coins left in the end, find the amount of money Ryan spent on the doll set.
|
20-cent coins |
50-cent coins |
Before |
8x7 = 56 u |
1x7 = 7 u |
Change |
- 51 u |
|
After |
5x1 = 5 u |
7x1 = 7 u |
Fraction of Ryan's savings that comprised of 50-cent coins
= 1 -
89=
19Number of 50-cents coins in the end in percentage
= 100% + 40%
= 140%
140% =
140100 =
75Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same. LCM of 1 and 7 is 7.
Number of more 50-cent coins than 20-cent coins
= 7 u - 5 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of 20-cent coins spent on the doll set
= 56 u - 5 u
= 51 u
= 51 x 10
= 510
Amount that Ryan spent on the doll set
= 510 x 0.2
= $102
Answer(s): $102