59 of Bryan's savings comprised of 20-cent coins and 50-cent coins. Bryan used some 20-cent coins to purchase a lego set. The number of 50-cent coins left was 25% more than the number of 20-cent coins left. Given that Bryan had 60 more 50-cent coins than 20-cent coins left in the end, find the amount of money Bryan spent on the lego set.
|
20-cent coins |
50-cent coins |
Before |
5x5 = 25 u |
4x5 = 20 u |
Change |
- 9 u |
|
After |
4x4 = 16 u |
5x4 = 20 u |
Fraction of Bryan's savings that comprised of 50-cent coins
= 1 -
59=
49Number of 50-cents coins in the end in percentage
= 100% + 25%
= 125%
125% =
125100 =
54Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same. LCM of 4 and 5 is 20.
Number of more 50-cent coins than 20-cent coins
= 20 u - 16 u
= 4 u
4 u = 60
1 u = 60 ÷ 4 = 15
Number of 20-cent coins spent on the lego set
= 25 u - 16 u
= 9 u
= 9 x 15
= 135
Amount that Bryan spent on the lego set
= 135 x 0.2
= $27
Answer(s): $27