58 of Reggie's savings comprised of 10-cent coins and 20-cent coins. Reggie used some 10-cent coins to purchase a lego set. The number of 20-cent coins left was 25% more than the number of 10-cent coins left. Given that Reggie had 30 more 20-cent coins than 10-cent coins left in the end, find the amount of money Reggie spent on the lego set.
|
10-cent coins |
20-cent coins |
Before |
5x5 = 25 u |
3x5 = 15 u |
Change |
- 13 u |
|
After |
4x3 = 12 u |
5x3 = 15 u |
Fraction of Reggie's savings that comprised of 20-cent coins
= 1 -
58=
38Number of 20-cents coins in the end in percentage
= 100% + 25%
= 125%
125% =
125100 =
54Number of 20-cent coins remains unchanged. Make the number of 20-cent coins the same. LCM of 3 and 5 is 15.
Number of more 20-cent coins than 10-cent coins
= 15 u - 12 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of 10-cent coins spent on the lego set
= 25 u - 12 u
= 13 u
= 13 x 10
= 130
Amount that Reggie spent on the lego set
= 130 x 0.1
= $13
Answer(s): $13