⁵₉ of Jenson's savings comprised of 20-cent coins and 50-cent coins. Jenson used some 20-cent coins to purchase a board game. The number of 50-cent coins left was 50% more than the number of 20-cent coins left. Given that Jenson had 60 more 50-cent coins than 20-cent coins left in the end, find the amount of money Jenson spent on the board game.

	20-cent coins	50-cent coins
Before	5x3 = 15 u	4x3 = 12 u
Change	- 7 u
After	2x4 = 8 u	3x4 = 12 u

Fraction of Jenson's savings that comprised of 50-cent coins
= 1 - ⁵₉
= ⁴₉

Number of 50-cents coins in the end in percentage
= 100% + 50%
= 150%

150% = ¹⁵⁰₁₀₀ = ³₂

Number of 50-cent coins remains unchanged. Make the number of 50-cent coins the same.  LCM of 4 and 3 is 12.

Number of more 50-cent coins than 20-cent coins
= 12 u - 8 u
= 4 u

4 u = 60

1 u = 60 ÷ 4 = 15

Number of 20-cent coins spent on the board game 
= 15 u - 8 u
= 7 u
= 7 x 15
= 105

Amount that Jenson spent on the board game 
= 105 x 0.2
= $21

Answer(s): $21