At first, Barrel S and Barrel T contained 0.5 ℓ and 3.2 ℓ of water respectively. Some water from Barrel T was poured into Barrel S with no water spilling over. In the end, there was as much water in Barrel S as in Barrel T. How much water was poured from Barrel T to Barrel S?
|
Barrel S |
Barrel T |
Difference |
Before |
0.5 ℓ |
3.2 ℓ |
3.7 ℓ |
Change |
+ 1.35 ℓ |
- 1.35 ℓ |
|
After |
1.85 ℓ |
1.85 ℓ |
|
Difference in the volume of water in Barrel S and Barrel T
= 3.2 - 0.5
= 2.7 ℓ
Volume of water poured from Barrel T to Barrel S
= 2.7 ÷ 2
= 1.35 ℓ
Answer(s): 1.35 ℓ