At first, Container S and Container T contained 0.7 ℓ and 1.8 ℓ of water respectively. Some water from Container T was poured into Container S with no water spilling over. In the end, there was as much water in Container S as in Container T. How much water was poured from Container T to Container S?
|
Container S |
Container T |
Difference |
Before |
0.7 ℓ |
1.8 ℓ |
2.5 ℓ |
Change |
+ 0.55 ℓ |
- 0.55 ℓ |
|
After |
1.25 ℓ |
1.25 ℓ |
|
Difference in the volume of water in Container S and Container T
= 1.8 - 0.7
= 1.1 ℓ
Volume of water poured from Container T to Container S
= 1.1 ÷ 2
= 0.55 ℓ
Answer(s): 0.55 ℓ