At first, Pot S and Pot T contained 0.3 ℓ and 2.4 ℓ of water respectively. Some water from Pot T was poured into Pot S with no water spilling over. In the end, there was as much water in Pot S as in Pot T. How much water was poured from Pot T to Pot S?
|
Pot S |
Pot T |
Difference |
Before |
0.3 ℓ |
2.4 ℓ |
2.7 ℓ |
Change |
+ 1.05 ℓ |
- 1.05 ℓ |
|
After |
1.35 ℓ |
1.35 ℓ |
|
Difference in the volume of water in Pot S and Pot T
= 2.4 - 0.3
= 2.1 ℓ
Volume of water poured from Pot T to Pot S
= 2.1 ÷ 2
= 1.05 ℓ
Answer(s): 1.05 ℓ