Hilda and Nora shared some necklaces. Hilda's share was 40% of Nora's share. She then increased her share of the necklaces by taking 20% of Nora's share. Given that Hilda had 30 fewer necklaces than Nora in the end, how many necklaces did the girls have altogether?
| |
Hilda |
Nora |
Difference |
Total |
| Before |
2 u |
5 u |
|
7 u |
| Change |
+ 1 u |
- 1 u |
|
|
| After |
3 u |
4 u |
1 u |
7 u |
40% =
40100 =
25Number of necklaces that Hilda took from Nora
= 20% x 5 u
=
20100 x 5 u
= 1 u
Number of fewer necklaces that Hilda had than Nora in the end = 1 u
1 u = 30
1 u = 30 ÷ 1 = 30
Total number of necklaces that the girls had
= 7 u
= 7 x 30
= 210
Answer(s): 210
