At the school, Floor P and Floor Q had an equal number of tables at first. If 9 tables were removed from Floor Q and 6 times as many tables were removed from Floor P as Floor Q, the number of tables in Floor Q would be 4 times as many as in Floor P. Find the number of tables on each floor.
| |
Floor P |
Floor Q |
| Before |
1 u + 54 |
4 u + 9 |
| Change |
- 54 |
- 9 |
| After |
1 u |
4 u |
Number of tables removed from Floor P
= 6 x 9
= 54
Number of tables on Floor P and Floor Q at first is the same.
4 u + 9 = 1 u + 54
4 u - 1 u = 54 - 9
3 u = 45
1 u = 45 ÷ 3 = 15
Number of tables on each floor
= 1 u + 54
= 15 + 54
= 69
Answer(s): 69
