At the hospital, Storey U and Storey V had an equal number of beds at first. If 8 beds were removed from Storey V and 7 times as many beds were removed from Storey U as Storey V, the number of beds in Storey V would be 4 times as many as in Storey U. Find the number of beds on each storey.
|
Storey U |
Storey V |
Before |
1 u |
1 u |
Change |
- 56 |
- 8 |
After |
1 u - 56 |
1 u - 8 |
Number of beds removed from Storey U
= 7 x 8
= 56
Number of beds on Storey U and Storey V at first is the same.
Number of beds on Storey V is 4 times as many as Storey U in the end. If the number of beds on Storey U increases by 4 times, the number of beds on Storey U and Storey V will be the same.
4(1 u - 56) = 1 u - 8
4 u - 224 = 1 u - 8
4 u - 1 u = 224 - 8
3 u = 216
1 u = 216 ÷ 3 = 72
Number of beds in each floor
= 1 u
= 72
Answer(s): 72