At the school, Level J and Level K had an equal number of chairs at first. If 7 chairs were removed from Level K and 5 times as many chairs were removed from Level J as Level K, the number of chairs in Level K would be 5 times as many as in Level J. Find the number of chairs on each level.

	Level J	Level K
Before	1 u	1 u
Change	- 35	- 7
After	1 u - 35	1 u - 7

Number of chairs removed from Level J
= 5 x 7
= 35

Number of chairs on Level J and Level K at first is the same.

Number of chairs on Level K is 5 times as many as Level J in the end. If the number of chairs on Level J increases by 5 times, the number of chairs on Level J and Level K will be the same.

5(1 u - 35) = 1 u - 7
5 u - 175 = 1 u - 7 
5 u - 1 u = 175 - 7
4 u = 168

1 u = 168 ÷ 4 = 42

Number of chairs in each floor
= 1 u
= 42

Answer(s): 42