At the office building, Level U and Level V had an equal number of tables at first. If 8 tables were removed from Level V and 3 times as many tables were removed from Level U as Level V, the number of tables in Level V would be 5 times as many as in Level U. Find the number of tables on each level.
| |
Level U |
Level V |
| Before |
1 u |
1 u |
| Change |
- 24 |
- 8 |
| After |
1 u - 24 |
1 u - 8 |
Number of tables removed from Level U
= 3 x 8
= 24
Number of tables on Level U and Level V at first is the same.
Number of tables on Level V is 5 times as many as Level U in the end. If the number of tables on Level U increases by 5 times, the number of tables on Level U and Level V will be the same.
5(1 u - 24) = 1 u - 8
5 u - 120 = 1 u - 8
5 u - 1 u = 120 - 8
4 u = 112
1 u = 112 ÷ 4 = 28
Number of tables in each floor
= 1 u
= 28
Answer(s): 28
