At the office building, Storey B and Storey C had an equal number of chairs at first. If 8 chairs were removed from Storey C and 6 times as many chairs were removed from Storey B as Storey C, the number of chairs in Storey C would be 3 times as many as in Storey B. Find the number of chairs on each storey.
|
Storey B |
Storey C |
Before |
1 u + 48 |
3 u + 8 |
Change |
- 48 |
- 8 |
After |
1 u |
3 u |
Number of chairs removed from Storey B
= 6 x 8
= 48
Number of chairs on Storey B and Storey C at first is the same.
3 u + 8 = 1 u + 48
3 u - 1 u = 48 - 8
2 u = 40
1 u = 40 ÷ 2 = 20
Number of chairs on each storey
= 1 u + 48
= 20 + 48
= 68
Answer(s): 68