At the school, Level E and Level F had an equal number of chairs at first. If 9 chairs were removed from Level F and 5 times as many chairs were removed from Level E as Level F, the number of chairs in Level F would be 3 times as many as in Level E. Find the number of chairs on each level.
| |
Level E |
Level F |
| Before |
1 u + 45 |
3 u + 9 |
| Change |
- 45 |
- 9 |
| After |
1 u |
3 u |
Number of chairs removed from Level E
= 5 x 9
= 45
Number of chairs on Level E and Level F at first is the same.
3 u + 9 = 1 u + 45
3 u - 1 u = 45 - 9
2 u = 36
1 u = 36 ÷ 2 = 18
Number of chairs on each level
= 1 u + 45
= 18 + 45
= 63
Answer(s): 63
