At the school, Storey U and Storey V had an equal number of tables at first. If 8 tables were removed from Storey V and 7 times as many tables were removed from Storey U as Storey V, the number of tables in Storey V would be 3 times as many as in Storey U. Find the number of tables on each storey.
| |
Storey U |
Storey V |
| Before |
1 u |
1 u |
| Change |
- 56 |
- 8 |
| After |
1 u - 56 |
1 u - 8 |
Number of tables removed from Storey U
= 7 x 8
= 56
Number of tables on Storey U and Storey V at first is the same.
Number of tables on Storey V is 3 times as many as Storey U in the end. If the number of tables on Storey U increases by 3 times, the number of tables on Storey U and Storey V will be the same.
3(1 u - 56) = 1 u - 8
3 u - 168 = 1 u - 8
3 u - 1 u = 168 - 8
2 u = 160
1 u = 160 ÷ 2 = 80
Number of tables in each floor
= 1 u
= 80
Answer(s): 80
