At the hospital, Floor S and Floor T had an equal number of beds at first. If 8 beds were removed from Floor T and 7 times as many beds were removed from Floor S as Floor T, the number of beds in Floor T would be 3 times as many as in Floor S. Find the number of beds on each floor.
| |
Floor S |
Floor T |
| Before |
1 u |
1 u |
| Change |
- 56 |
- 8 |
| After |
1 u - 56 |
1 u - 8 |
Number of beds removed from Floor S
= 7 x 8
= 56
Number of beds on Floor S and Floor T at first is the same.
Number of beds on Floor T is 3 times as many as Floor S in the end. If the number of beds on Floor S increases by 3 times, the number of beds on Floor S and Floor T will be the same.
3(1 u - 56) = 1 u - 8
3 u - 168 = 1 u - 8
3 u - 1 u = 168 - 8
2 u = 160
1 u = 160 ÷ 2 = 80
Number of beds in each floor
= 1 u
= 80
Answer(s): 80
