At the school, Floor R and Floor S had an equal number of chairs at first. If 6 chairs were removed from Floor S and 5 times as many chairs were removed from Floor R as Floor S, the number of chairs in Floor S would be 4 times as many as in Floor R. Find the number of chairs on each floor.

	Floor R	Floor S
Before	1 u	1 u
Change	- 30	- 6
After	1 u - 30	1 u - 6

Number of chairs removed from Floor R
= 5 x 6
= 30

Number of chairs on Floor R and Floor S at first is the same.

Number of chairs on Floor S is 4 times as many as Floor R in the end. If the number of chairs on Floor R increases by 4 times, the number of chairs on Floor R and Floor S will be the same.

4(1 u - 30) = 1 u - 6
4 u - 120 = 1 u - 6 
4 u - 1 u = 120 - 6
3 u = 114

1 u = 114 ÷ 3 = 38

Number of chairs in each floor
= 1 u
= 38

Answer(s): 38