At the school, Storey B and Storey C had an equal number of chairs at first. If 8 chairs were removed from Storey C and 3 times as many chairs were removed from Storey B as Storey C, the number of chairs in Storey C would be 3 times as many as in Storey B. Find the number of chairs on each storey.
| |
Storey B |
Storey C |
| Before |
1 u + 24 |
3 u + 8 |
| Change |
- 24 |
- 8 |
| After |
1 u |
3 u |
Number of chairs removed from Storey B
= 3 x 8
= 24
Number of chairs on Storey B and Storey C at first is the same.
3 u + 8 = 1 u + 24
3 u - 1 u = 24 - 8
2 u = 16
1 u = 16 ÷ 2 = 8
Number of chairs on each storey
= 1 u + 24
= 8 + 24
= 32
Answer(s): 32
