At the factory, Floor A and Floor B had an equal number of machines at first. If 8 machines were removed from Floor B and 5 times as many machines were removed from Floor A as Floor B, the number of machines in Floor B would be 3 times as many as in Floor A. Find the number of machines on each floor.
| |
Floor A |
Floor B |
| Before |
1 u + 40 |
3 u + 8 |
| Change |
- 40 |
- 8 |
| After |
1 u |
3 u |
Number of machines removed from Floor A
= 5 x 8
= 40
Number of machines on Floor A and Floor B at first is the same.
3 u + 8 = 1 u + 40
3 u - 1 u = 40 - 8
2 u = 32
1 u = 32 ÷ 2 = 16
Number of machines on each floor
= 1 u + 40
= 16 + 40
= 56
Answer(s): 56
