At the school, Level B and Level C had an equal number of chairs at first. If 6 chairs were removed from Level C and 5 times as many chairs were removed from Level B as Level C, the number of chairs in Level C would be 3 times as many as in Level B. Find the number of chairs on each level.
|
Level B |
Level C |
Before |
1 u + 30 |
3 u + 6 |
Change |
- 30 |
- 6 |
After |
1 u |
3 u |
Number of chairs removed from Level B
= 5 x 6
= 30
Number of chairs on Level B and Level C at first is the same.
3 u + 6 = 1 u + 30
3 u - 1 u = 30 - 6
2 u = 24
1 u = 24 ÷ 2 = 12
Number of chairs on each level
= 1 u + 30
= 12 + 30
= 42
Answer(s): 42