At the factory, Floor B and Floor C had an equal number of machines at first. If 8 machines were removed from Floor C and 7 times as many machines were removed from Floor B as Floor C, the number of machines in Floor C would be 3 times as many as in Floor B. Find the number of machines on each floor.
| |
Floor B |
Floor C |
| Before |
1 u + 56 |
3 u + 8 |
| Change |
- 56 |
- 8 |
| After |
1 u |
3 u |
Number of machines removed from Floor B
= 7 x 8
= 56
Number of machines on Floor B and Floor C at first is the same.
3 u + 8 = 1 u + 56
3 u - 1 u = 56 - 8
2 u = 48
1 u = 48 ÷ 2 = 24
Number of machines on each floor
= 1 u + 56
= 24 + 56
= 80
Answer(s): 80
