At the school, Storey X and Storey Y had an equal number of tables at first. If 8 tables were removed from Storey Y and 7 times as many tables were removed from Storey X as Storey Y, the number of tables in Storey Y would be 4 times as many as in Storey X. Find the number of tables on each storey.
| |
Storey X |
Storey Y |
| Before |
1 u |
1 u |
| Change |
- 56 |
- 8 |
| After |
1 u - 56 |
1 u - 8 |
Number of tables removed from Storey X
= 7 x 8
= 56
Number of tables on Storey X and Storey Y at first is the same.
Number of tables on Storey Y is 4 times as many as Storey X in the end. If the number of tables on Storey X increases by 4 times, the number of tables on Storey X and Storey Y will be the same.
4(1 u - 56) = 1 u - 8
4 u - 224 = 1 u - 8
4 u - 1 u = 224 - 8
3 u = 216
1 u = 216 ÷ 3 = 72
Number of tables in each floor
= 1 u
= 72
Answer(s): 72
